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sync: allow --max-backlog to be -ve meaning as large as possible

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This commit is contained in:
Nick Craig-Wood 2020-05-15 11:23:16 +01:00
parent 7f44735709
commit 147f97d1f7
2 changed files with 7 additions and 0 deletions
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3
docs/content/docs.md
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@ -745,6 +745,9 @@ time and make `--order-by` work more accurately.
Setting this small will make rclone more synchronous to the listings
of the remote which may be desirable.
Setting this to a negative number will make the backlog as large as
possible.
### --max-delete=N ###
This tells rclone not to delete more than N files. If that limit is

4
fs/sync/pipe.go
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@ -2,6 +2,7 @@ package sync
import (
"context"
"math/bits"
"strconv"
"strings"
"sync"
@ -30,6 +31,9 @@ type pipe struct {
}
func newPipe(orderBy string, stats func(items int, totalSize int64), maxBacklog int) (*pipe, error) {
if maxBacklog < 0 {
maxBacklog = (1 << (bits.UintSize - 1)) - 1 // largest posititive int
}
less, fraction, err := newLess(orderBy)
if err != nil {
return nil, fserrors.FatalError(err)